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Unexpected T_CONSTANT_ENCAPSED_STRING error in SQL Query

开发者 https://www.devze.com 2023-02-18 10:40 出处:网络
I am getting an unexpected T_CONSTANT_ENCAPSED_STRING error in the following SQL query: mysql_query (UPDATE \'wp_posts\' SET \'post_status\' = \'publish\' WHERE \'post_id\' = \'$id\');

I am getting an unexpected T_CONSTANT_ENCAPSED_STRING error in the following SQL query:

mysql_query (UPDATE 'wp_posts' SET 'post_status' = 'publish' WHERE 'post_id' = '$id');

Can you g开发者_JAVA技巧uys see where the error might be?

Here is the full code in case it helps:

    $key = 'feed';
    $post_ids = array(2263, 2249); 

    foreach ($post_ids as $id) {
    $feedurl = get_post_custom_values($key, $id);
    $feedurlstr = implode($feedurl);

    // Ignore - it determines whether feed is live and returns $result
    LiveOrNot($feedurlstr);

    if ( $result == "live" ) {
    mysql_query (UPDATE 'wp_posts' SET 'post_status' = 'publish' WHERE 'post_id' = '$id');
    }    
    elseif ( $result == "notlive" ) {
    mysql_query (UPDATE 'wp_posts' SET 'post_status' = 'draft' WHERE 'post_id' = '$id');
    }
    endif;
    }


Wrap your SQL statements in quote-marks - ".

mysql_query ("UPDATE 'wp_posts' SET 'post_status' = 'publish' WHERE 'post_id' = '$id'");


mysql_query() takes a string. PHP is looking for constants interspersed with strings, which is not valid PHP grammer.

You need to delimit your strings, ' and " are popular choices, but there is also Heredoc syntax.

Read more about strings in PHP.

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