Correct way to escape a string in PHP when there are row['value'] in the string?

The code below is returned to an html page in an object using AJAX.

It doesn't seem to do what It does when I am not echoing it as PHP, which is to sort the DIVS as they are created based on the attribute 'data-sort'

I know that the function is correct, am I perhaps escaping it incorrectly?

echo "

        newdiv = $(\'<div id=\'eventdiv\' class=\'shadow curved_sml gradient\' data-sort=\'".$row_display['TimeStamp']."\'>".$row_new['Title']." TIME: ".$row_display['TimeStamp']."开发者_Python百科</div>\');

        div_id_after = Math.floor(parseFloat(newdiv.attr('data-sort')));

        $('div[data-sort='+div_id_after+']').after(newdiv);

        ";

Regards, Taylor

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Yes, you are escaping it incorrectly. What you have is:

• first level of quotes: double ones, in PHP,
• second level of quotes: single ones, in JavaScript,

but you have incorrect quotes in the third level - HTML passed as string in JS, which in turn is passed as string in PHP. Also you should not escape ''s, because you enclosed them in "'s.

Try the following:

echo "
    newdiv = $('<div id=\"eventdiv\" class=\"shadow curved_sml gradient\" data-sort=\"" . $row_display['TimeStamp'] . "\">" . $row_new['Title'] . " TIME: " . $row_display['TimeStamp'] . "</div>');

    div_id_after = Math.floor(parseFloat(newdiv.attr('data-sort')));

    $('div[data-sort=\"'+div_id_after+'\"]').after(newdiv);
";

I think this should solve your problem. But I did not test it.

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Yes, you are - in a double-quoted string, you don't escape single quotes. Remove all of those \'s and replace them with just '.