How to use delay() with each()?

$("#home #oneTool").prepend($(".userInfo.module"));

var topVal = $(".userInfo.module").height();
$(".userInfo.module").hide();
$(".userInfo.module").slideDown(3000);

$("#home #oneTool div.divspot").each(function(){
   var newVal = topVal + parseInt($(this).css('top'));
   $(this).css('top',newVal);
});

The .u开发者_开发知识库serInfo.module is present above all div.divspots...

Since i'm using slideDown, the each function needs to be delayed, so that the div.divspots could also slidedown smoothly.. (will delay be helpful?)

Note: All div.divspots are absolutely positioned

---

Well first of all, slideDown takes as a parameter a function to call after it's done. http://api.jquery.com/slideDown/

Props to another answerer who realized what you were asking and a #fail to me for not reading your question properly.

That being said, for a method that does not have a callback after completion, here are a couple of options.

Two options:

1. Use queue
2. Use setTimeout

Use queue:

http://api.jquery.com/queue/

$(".userInfo.module").fooThatTakes(3000).queue(function() {
  $("#home #oneTool div.divspot").each(function(){
    var newVal = topVal + parseInt($(this).css('top'));
    $(this).css('top',newVal);
  });
});

Use setTimeout.

var delay = 3000;
$(".userInfo.module").fooThatTakes(delay);
t = setTimeout(afterFoo, delay);

function afterFoo() {
  $("#home #oneTool div.divspot").each(function(){
    var newVal = topVal + parseInt($(this).css('top'));
    $(this).css('top',newVal);
  });
}

---

If I've understood your question correctly, then you want to run your each function after the slideDown is complete. If that's right, then you can use a callback to the slideDown function:

$(".userInfo.module").slideDown(3000, function() {
    //Your each function
});

The callback will run upon completion of the animation.