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Generic Type parameters

开发者 https://www.devze.com 2023-03-26 02:44 出处:网络
Please explain why this doesn\'t work? What is it about the constraint IPoolable<T> that the compiler doesn\'t like? Is it because the generic IPoolable<T> is really just a \"template\" an

Please explain why this doesn't work? What is it about the constraint IPoolable<T> that the compiler doesn't like? Is it because the generic IPoolable<T> is really just a "template" and there is no inheritance between PoolItem and IPollable<T>?

In the code

public class GenericPool<TPoolable> where TPoolable : IPoolable<T>

while can't T be interpreted as long?

Full code listing:

    public interface IPoolab开发者_运维问答le<T> where T : new()
    {
        T PooledObject { get; }
    }

    public class PoolItem : IPoolable<long>
    {
        private readonly long _id;

        public long PooledObject
        {
            get { return _id; }
        }
    }

    public class GenericPool<TPoolable> where TPoolable : IPoolable<T>
    {
        public T Borrow()
        {
            var item = default(TPoolable);
            return item.PooledObject;
        }

        public void Return(T item)
        {

        }
    }

    class Program
    {
        static void Main(string[] args)
        {
            var pool = new GenericPool<PoolItem>();
        }
    }

Just to be clear, I know that I can change GenericPool to

public class GenericPool<TPoolable, T> where TPoolable : IPoolable<T> where T : new()

I am not asking how to fix this code. Instead I am asking the question; why do I have to add T as a type parameter to GenericPool in the first place?


You can't use IPoolable<T> as a constraint because the generic type parameter T isn't known in that context. As you surmise, IPoolable<T> is essentially a blueprint for an infinite number of types, so without binding T to something (for example, a type parameter of the GenericPool class) it doesn't make sense as a constraint.

The actual error message you should be getting is The type or namespace name 'T' could not be found, which makes sense: T isn't defined anywhere.

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