Calling template function within template class

Disclaimer: The following question probably is so easy that I might be shocked seeing the first answer. Furthermore, I want to apologize for any duplicate questions - syntactic problems are not always easy to identify be verbal explanation and thus searching for them is not as easy...

But enough of that. I have a two templated classes, one of those has a templated member function, the other class attempts to call that function. A minimal, error producing example is shown below:

#include <iostream>

template <typename T>
class Foo {
public:
    Foo() {
    }

    template <typename o开发者_开发知识库uttype>
    inline outtype bar(int i, int j, int k = 1) {
        return k;
    }

};

template <typename T>
class Wrapper {
public:
    Wrapper() {
    }

    double returnValue() {
        Foo<T> obj;
        return obj.bar<double>(1,2); // This line is faulty.
    }

};

int main() {
    Wrapper<char> wr;
    double test = wr.returnValue();
    std::cout << test << std::endl;
    return 0;
}

At compile time, this results in

expected primary-expression before 'double'
expected ';' before 'double'
expected unqualified-id before '>' token

where all error messages are directed at the linke marked in the code.

I allready thank you for your ideas, no matter how obvious they are.

---

obj.bar<double>(1,2); // This line is faulty.

The template keyword is required here, as obj is an instance of a type Foo<T> which depends on the template parameter T, and so the above should be written as:

obj.template bar<double>(1,2); //This line is corrected :-)

Read @Johannes's answer here for detail explanation:

• Where and why do I have to put the "template" and "typename" keywords?

---

As so often: Once the question was posted, the answer came all by itself. Correcting the faulty line to

return obj.template bar<double>(1,2);

yields the expected results.

Thanks for reading...

---

Could this be a case of foo.template bar‹ double >?