Django URLS, how to map root to app?

I am pretty new to django but experienced in Python and java web programming with different frameworks. I have made myself a nice little django app, but I cant seem to make it match www.mysite.co开发者_开发技巧m as opposed to www.mysite.com/myapp.

I have defined urls and views in my urls.conf which is currently not decoupled from the app (don't mind that).

urlpatterns = patterns('myapp.views',
  (r'^myapp/$', 'index'),
  (r'^myapp/(?P<some_id>\d+)/global_stats/$', 'global_stats'),
  (r'^myapp/(?P<some_id>\d+)/player/(?P<player_id>\d+)/$', 'player_stats'),
)

All this works like a charm. If someone goes to www.mysite.com/myapp they will hit my index view which causes a http redirect to my "correct" default url.

So, how can I add a pattern that will do the same as (r'^myapp/$', 'index') but without the /myapp--that is, www.mysite.com should suffice?

I would think this would be very basic stuff... I tried adding a line like:

(r'^$', 'index'),

however this throws me in a loop...

Hope you django gurus out there can clarify this for me!

---

I know that this question was asked 2 years ago, but I've faced the same problem and found a solution:

In the project urls.py:

urlpatterns = patterns('',
    url(r'^', include('my_app.urls')), #NOTE: without $
)

In my_app.urls.py:

urlpatterns = patterns('',
    url(r'^$', 'my_app.views.home', name='home'),
    url(r'^v1/$', 'my_app.views.v1', name='name_1'),
    url(r'^v2/$', 'my_app.views.v2', name='name_2'),
    url(r'^v3/$', 'my_app.views.v3', name='name_3'),
)

---

This sounds strange.

Your latest attempt should work, but what I normally do - put

urlpatterns = patterns('',
    (r'^$', lambda r: HttpResponseRedirect('myapp/')),
    ...
)

This scales better when you start adding new apps.

---

As I didn't see any answer for django 2.0 I thought I'll provide one. you have to use '' as the root url. Here is an example from django 2.0 docs

urlpatterns = [
    path('', main_views.homepage),
    path('help/', include('apps.help.urls')),
    path('credit/', include(extra_patterns)),
]

---

Just put an empty raw regular expression: r''

I tested here and it worked perfectly.

urlpatterns = patterns('',
    url(r'', include('homepage.urls')),
    url(r'^homepage/', include('homepage.urls')),
    url(r'^admin/', include(admin.site.urls)),
)

Hope it help!

---

I also wanted to have the root of my domain to directly point to a view of a sub app.

At first I created the sub app with this command:

python3 manage.py startapp main offer_finder/main

In your case it would be:

python3 manage.py startapp myApp project/somedirectory/myApp

make sure that the directory exists: mkdir -p project/somedirectory/myApp

This is my project structure: Project structure

In my case I have these directories:

offer_finder_project/offer_finder/main        # sub app  
offer_finder_project/offer_finder/            # main source directory  

in offer_finder_project/offer_finder/urls.py I have this code:

from django.contrib import admin
from django.urls import path, include


urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include('offer_finder.main.urls')),
]

And in offer_finder_project/offer_finder/main/urls.py I have this code:

from django.urls import path
from . import views

urlpatterns = [
    path('', views.index),
]

And the offer_finder_project/offer_finder/main/views.py file simply contains some test code.

from django.http import HttpResponse

def index(request):
    return HttpResponse("TEST app index")

This way your requests to your root domain are directed to your sub app. Hopefully this helps someone. This code was tested with Django 2.1.4.

---

old question here ... (as much as myself :o)
but still worth of sharing updates for Django 3.x:

In project urls.py just add:

urlpatterns = [
    path('', include('myapp.urls')), 
    path('myapp/', include('myapp.urls')),
    #path('admin/', admin.site.urls),
]

Be aware that this solution will monopolize the whole django to your hungry&selfish app :-) !!!

---

I know the answer is late, but i had my fair share of hunting recently. This is what i tried with CBV.. in Project urls.py

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^$', include('app_name.urls', namespace='app_name')),
]

PS: It is always recommended to use namespace. Gives a good advantage later on.

In App urls.py

urlpatterns = [
    url(r'^$', views.IndexPageView.as_view(), name='index'),
]