开发者

Submitting a form without refreshing the page

开发者 https://www.devze.com 2023-04-11 11:36 出处:网络
I\'m having a problem with jQuery(or maybe php). I want forms to be submitted without refreshing the page so i ended up with the following code but the problem is it doesn\'t wo开发者_运维问答rk. Here

I'm having a problem with jQuery(or maybe php). I want forms to be submitted without refreshing the page so i ended up with the following code but the problem is it doesn't wo开发者_运维问答rk. Here's the code:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript" src="jquery.js"></script>
<script type="text/javascript">
                $("#submit").click(function() {
                var name = $("#name").val();

                var dataString = 'name='+ name;

                $.ajax({
                type: "POST",
                url: "p.php",
                data: dataString,
                success: function(){
                    alert("It works");

                }
                });
                return false;

            });
</script>
</head>

<body>
<form id="myForm" name="myForm" action="">
  <p>
    <label for="name"></label>
    <input type="text" name="name" id="name" />
  </p>
  <p>
    <input type="submit" name="submit" id="submit" value="Submit" />
  </p>
</form>
<br />
</body>
</html>

Processing Page:

<?php include("../includes/includes.php"); ?>
<?php $name = $_POST['name']; ?>
<?php $sql = "INSERT INTO xyz 
        (id, value) VALUES 
            (1, '{$name}')";
        $result = $database->query($sql);
?>


i dont know why its not working but you can try like this

<form id="myForm" name="myForm" action="">
  <p>
    <label for="name"></label>
    <input type="text" name="name" id="name" />
  </p>  
  <p>
     <input type="button" name="submit" id="submit" value="Submit" />//change type to button
  </p>
</form>

also make an error callback

$(function(){
 $("#submit").click(function(e) {
                e.preventDefault();
                var name = $("#name").val();
                $.ajax({
                type: "POST",
                url: "p.php",
                data: {name:name},
                success: function(){
                    alert("It works");
                },
                error:function(e){alert("it failed");}
                });

            });   

});


You need to modify your form tag like this:

<form id="myForm" name="myForm" action="" onsubmit="return false;">
0

精彩评论

暂无评论...
验证码 换一张
取 消

关注公众号