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Why is this C program reporting more throughput than nload?

开发者 https://www.devze.com 2023-04-11 22:28 出处:网络
I run the following C program between two machines with 10GibE; the program reports 12Gib/s whereas nload reports a (more believable) 9.2Gib/s.Can anyone tell me what I\'m doing wrong in the program?

I run the following C program between two machines with 10GibE; the program reports 12Gib/s whereas nload reports a (more believable) 9.2Gib/s. Can anyone tell me what I'm doing wrong in the program?

.
.
#define BUFFSZ (4*1024)
char buffer[BUFFSZ];
.
.
  start = clock();

  while (1) {
    n = write(sockfd, buffer, BUFFSZ);
    if (n < 0)
       error开发者_运维知识库("ERROR writing to socket");
    if (++blocks % (1024*1024) == 0)
    {
      blocks = 0;
      printf("32Gib at %6.2lf Gib/s\n", 32.0/(((double) (clock() - start)) / CLOCKS_PER_SEC));
      start = clock();
    }
  }

This is CentOs 6.0 on Linux 2.6.32; nload 0.7.3, gcc 4.4.4.


Firstly, clock() returns an estimate of the CPU time used by the program, not the wall-clock time - so your calculation indicates that you are transferring 12GiB per second of CPU time used. Instead, use clock_gettime() with the clock ID CLOCK_MONOTONIC to measure wall-clock time.

Secondly, after write() returns the data hasn't necessarily been sent to the network yet - merely copied into the kernel buffers for sending. This will give you a higher reported transfer rate at the start of the connection.


Check the return value from read() n might be shorter than BUFFSZ.

EDIT: oops, that should have been write().

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