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How to pass arguments into variables to eventually execute in a batch file?

开发者 https://www.devze.com 2023-04-12 20:47 出处:网络
I\'m looking to create an App file wrapper that will take 3 arguments with an optional 4th argument.The 1st argument will be the location of a directory that needs \"work\" done, the 2nd and 3rd argum

I'm looking to create an App file wrapper that will take 3 arguments with an optional 4th argument. The 1st argument will be the location of a directory that needs "work" done, the 2nd and 3rd arguments should be appended together as one argument to run an application, and the 4th argument will be a switch.

Ex: AppFileWrapper C:\Application\ App begin-work -New

1st argument: C:\Application

2nd argument: App

3rd argument: begin-work

4th开发者_Go百科 argument (optional): -New

What I need is a batch file that will automatically navigate to the given directory, and then execute the remaining arguments as: "App begin-work -New"

I've created the following batch file

cd %1
set var1=%2 %3 %4

Now how to just call var1 or "App begin-work -New" or "App begin-work" as specified by the parameters.

Thanks, I'm completely new to creating batch files.


cd %1
start %2 %3 %4

should work.

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