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Subtracting months/years from boost::posix_time::ptime

开发者 https://www.devze.com 2022-12-23 10:21 出处:网络
I have a boost::posix_time::ptime that points to March 31st 2010 like this: ptime p(date(2010, Mar, 31));

I have a boost::posix_time::ptime that points to March 31st 2010 like this:

ptime p(date(2010, Mar, 31));

开发者_StackOverflow中文版I would like to subtract a month (and possibly years) from this date. From the docs I see these two operators: ptime operator-(time_duration) and ptime operator-(days) but none of them can work with months/years. If I try and do:

time_duration duration = hours(24 * 30);
ptime pp = p - duration;

I'm getting March 1st and if I'm trying:

ptime pp = p - days(30);

I'm still getting March 1st, while I'd like to get February 28th.

How can I achieve my desired result? (I would like to get the desired result also when subtracting a month from March 28, 29, 30)


boost::posix_time::ptime::date() operator returns date object. You can call greg_year, greg_month etc. for this object.


Well, I guess you already know that not all months have 30 days so you can't subtract with 30 days in general.

You should ask yourself what you mean by "subtract a month".

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