mysql-error-1064
Mysql replace() function, help with query (what chars do I escape?)
I am trying to update an old cms where images were stored in /images/editor/, they开发者_如何学Go are now stored in a bucket on amazon s3. I\'m trying to update the database using mysql replace. I\'ve[详细]
2023-02-02 13:19 分类:问答SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax — PHP — PDO [duplicate]
This question already has an answer here: Syntax error due to using a reserved word as a table or column name in MySQL[详细]
2023-02-01 16:51 分类:问答ALTER TABLE ORDER BY str_to_date and time_to_sec
I am trying to re-order a table after importing a file but am getting a mysq开发者_Go百科l syntax error on this query:[详细]
2023-01-31 22:01 分类:问答Infobright Enterprise Edition (IEE) service won't start?
I went to www.infobright.com, downloaded Infobright Enterprise Ed开发者_如何学Cition (IEE), and installed it. However, the service won\'t start, and it gives me absolutely no hint as to what the error[详细]
2023-01-31 19:57 分类:问答MySQL Subqueries Not Working, Generating Error Code 1064
This query doesn\'t work SELECT * FROM Catalogue WHERE Catalogue.ID IN ( SELECT ID_catalogue FROM Categories WHERE Categories.Product_type=\'xxx\'[详细]
2023-01-30 15:39 分类:问答Java PreparedStatement SQL Syntax for LIKE
I have a prepared statement as so: private static final String SQL_LIST_GROUP = \"SELECT * FROM table[详细]
2023-01-30 04:06 分类:问答What's wrong in this simple PHP SQL sentence?
i want to recober all the users with \"blo\" in their full name, for example: \"Pablo\" I pass the \"blo\" parameter with user PHP parameter:[详细]
2023-01-30 00:08 分类:问答insert - not recorded field in the table
INSERT INTO `jos1_content` (`title`, `introtext`, `fulltext`, `state`, `sectionid`, `catid`, `attribs`)[详细]
2023-01-29 21:48 分类:问答SQL syntax: passing variable to SQL query
This is my first program and I have done extensive research trying to answer this question and I can not solve the problem:[详细]
2023-01-29 18:25 分类:问答How does mysql delete syntax differ from select?
This: SELECT * FROM tbl_playlists, tbl_playlistsongs WHERE tbl_playlists.playlist_id = tbl_playlistsongs.playlist_id[详细]
2023-01-29 04:17 分类:问答
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