python-itertools

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python: how to make a product of iterables without repeating the items?

I need a function that functions in a similar manner as itertools.product, but without repeating items.[详细]

2023-03-10 16:13 分类：问答
How to turn the result (in python) of itertools.permutations("0123456789") into list of strings

In Python, I am using list(itertools.permutations(\"0123456789\")), and I am receiving (I as expected) a list of tuples of singled character strings.[详细]

2023-02-17 17:25 分类：问答
itertools.chain to chain an iter list?

import itertools def _yield_sample(): it = iter(itertools.combinations(\'ABCD\', 2开发者_如何学Go))[详细]

2023-02-15 22:51 分类：问答
Generate Binary Table with Itertools

So this is what im trying list(itertools.combinations_with_replacement(\'01\', 2)) but this is开发者_StackOverflow社区 generating [(\'0\', \'0\'), (\'0\', \'1\'), (\'1\', \'1\')][详细]

2023-02-15 16:11 分类：问答
implementing argmax in Python

How should argmax be implemented in Pyth开发者_JAVA技巧on?It should be as efficient as possible, so it should work with iterables.[详细]

2023-02-13 14:53 分类：问答
How do I reverse an itertools.chain object?

My function creates a chain of generators: def bar(num): import itertools some_sequence = (x*1.5 for x in range(num))[详细]

2023-02-11 04:26 分类：问答
Python: itertools.islice not working in a loop

I have code like this: #opened file f goto_line = num_lines #Total number of lines w开发者_运维技巧hile not found:[详细]

2023-02-11 02:30 分类：问答
When is it better to use zip instead of izip?

When is it b开发者_JS百科etter to use zip instead of itertools.izip?zip computes all the list at once, izip computes the elements only when requested.[详细]

2023-02-10 13:20 分类：问答
Optimize generator for multivariate polynomial exponents

HI, I\'m try to find a general expression to obtain exponents of a multivariate polynomial of order order and with n_variables, like the one presented in this reference in equation (3).[详细]

2023-02-09 08:57 分类：问答
itertools product speed up

I use itertools.product to generate all possible variations of 4 elements of length 13. The 4 and 13 can be arbitrary, but as it is, I get 4^13 results, which is a lot. I need the result as a Numpy ar[详细]

2023-02-04 20:04 分类：问答