Deserializing Map<Object, Object> with GSon

I have a Map containing a mixture of types like in this simple example

final Map<String, Object> map = new LinkedHashMap<String, Object>();
map.put("a", 1);
map.put("b", "a");
map.put("c", 2);
final Gson gson = new Gson();
final String string = gson.toJson(map);
final Type type = new TypeToken<LinkedHashMap<String, Object>>(){}.getType();
final Map<Object, Object> map2 = gson.fromJson(string, type);
for (final Entry<Object, Object> entry : map2.entrySet()) {
    System.out.println(entry.getKey() + " : " + entry.getValue());
}

What I get back are plain Objects, no Integers, no Strings. The output looks like

a : 开发者_JAVA百科java.lang.Object@48d19bc8
b : java.lang.Object@394a8cd1
c : java.lang.Object@4d630ab9

Can I fix it somehow? I'd expect that such simple cases will be handled correctly by default.

^{I know that the information about the type can't always be preserved, and possibly 1 and "1" means exactly the same in JSON. However, returning plain content-less objects just makes no sense to me.}

Update: The serialized version (i.e. the string above) looks fine:

{"a":1,"b":"a","c":2}

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Gson isn't that smart. Rather provide a clear and static data structure in flavor of a Javabean class so that Gson understands what type the separate properties are supposed to be deserialized to.

E.g.

public class Data {
    private Integer a;
    private String b;
    private Integer c;
    // ...
}

in combination with

Data data1 = new Data(1, "a", 2);
String json = gson.toJson(data1);
Data data2 = gson.fromJson(json, Data.class);

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Update: as per the comments, the keyset seems to be not fixed (although you seem to be able to convert it manually afterwards without knowing the structure beforehand). You could create a custom deserializer. Here's a quick'n'dirty example.

public class ObjectDeserializer implements JsonDeserializer<Object> {

    @Override
    public Object deserialize(JsonElement element, Type type, JsonDeserializationContext context) throws JsonParseException {
        String value = element.getAsString();
        try {
            return Long.valueOf(value);
        } catch (NumberFormatException e) {
            return value;
        }
    }

}

which you use as follows:

final Gson gson = new GsonBuilder().registerTypeAdapter(Object.class, new ObjectDeserializer()).create();
// ... 

---

Gson gson = new GsonBuilder()
    .registerTypeAdapter(Object.class, new JsonDeserializer<Object>() {
      @Override
      public Object deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context) throws JsonParseException {
        JsonPrimitive value = json.getAsJsonPrimitive();
        if (value.isBoolean()) {
          return value.getAsBoolean();
        } else if (value.isNumber()) {
          return value.getAsNumber();
        } else {
          return value.getAsString();
        }
      }
    }).create();

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Upgrade to Gson 2.1. It prints this:

a : 1.0
b : a
c : 2.0

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You are storing the data in a Map. It looks like you need to cast the object to the type you need.

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If you want a JSON string from Map<Object, Object>, I think json-simple is better choice than Gson.

This is a brief example from http://code.google.com/p/json-simple/wiki/EncodingExamples :

//import java.util.LinkedHashMap;
//import java.util.Map;
//import org.json.simple.JSONValue;

Map obj=new LinkedHashMap();
obj.put("name","foo");
obj.put("num",new Integer(100));
obj.put("balance",new Double(1000.21));
obj.put("is_vip",new Boolean(true));
obj.put("nickname",null);
String jsonText = JSONValue.toJSONString(obj);
System.out.print(jsonText);

Result: {"name":"foo","num":100,"balance":1000.21,"is_vip":true,"nickname":null}

For decoding, refer to http://code.google.com/p/json-simple/wiki/DecodingExamples .