String to list in Python

I'm trying to split a string:

'QH QD JC KD JS'

into a list like:

['QH', 'QD', 'JC', 'KD', 'JS开发者_高级运维']

How would I go about doing this?

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>>> 'QH QD JC KD JS'.split()
['QH', 'QD', 'JC', 'KD', 'JS']

split:

Return a list of the words in the string, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done (thus, the list will have at most maxsplit+1 elements). If maxsplit is not specified, then there is no limit on the number of splits (all possible splits are made).

If sep is given, consecutive delimiters are not grouped together and are deemed to delimit empty strings (for example, '1,,2'.split(',') returns ['1', '', '2']). The sep argument may consist of multiple characters (for example, '1<>2<>3'.split('<>') returns ['1', '2', '3']). Splitting an empty string with a specified separator returns [''].

If sep is not specified or is None, a different splitting algorithm is applied: runs of consecutive whitespace are regarded as a single separator, and the result will contain no empty strings at the start or end if the string has leading or trailing whitespace. Consequently, splitting an empty string or a string consisting of just whitespace with a None separator returns [].

For example, ' 1 2 3 '.split() returns ['1', '2', '3'], and ' 1 2 3 '.split(None, 1) returns ['1', '2 3 '].

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Here the simples

a = [x for x in 'abcdefgh'] #['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']

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Maybe like this:

list('abcdefgh') # ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h']

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Or for fun:

>>> ast.literal_eval('[%s]'%','.join(map(repr,s.split())))
['QH', 'QD', 'JC', 'KD', 'JS']
>>> 

ast.literal_eval

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You can use the split() function, which returns a list, to separate them.

letters = 'QH QD JC KD JS'

letters_list = letters.split()

Printing letters_list would now format it like this:

['QH', 'QD', 'JC', 'KD', 'JS']

Now you have a list that you can work with, just like you would with any other list. For example accessing elements based on indexes:

print(letters_list[2])

This would print the third element of your list, which is 'JC'