Use a wildcard as a directory level in PHP

What is the best way to skip ov开发者_StackOverflower a directory level in PHP using some kind of wildcard expression?

I have a config.php file that is unique to each child directory and I need to include it in the header of my page.

Example:

http://mysite.com/dir1/dir2/could-be-anything/config.php
http://mysite.com/dir1/dir2/something-different/config.php
http://mysite.com/dir1/dir2/different-again/config.php

What I want is to tell my main PHP page to include config.php when the name of it's parent directory may change?

Something like <?php include("http://mysite.com/dir1/dir2/*/config.php"); ?>

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You want to use glob and a foreach to include each file that matches.

foreach (glob("path/*/config.php") as $config)
    include($config);

See the man page on glob for more specifics.

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If the location is defined by dir1 and dir2 and the third one is simply a readable unkown, then you can accomplish it with a single expression:

include(current(glob("./dir1/dir2/*/config.php")));

_{Note: Loading an include script over http://mysite/... is not possible. HTTP provides no directory listings, and it wouldn't work because that config.php script would be parsed away in that case.}