Define function to find the last even digit using recursion

Suppos开发者_运维知识库e input no is f(354683257) returns 2.

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It sounds like you can break this into two easier problems.

• How do you find the last digit of a given number?
• How do you strip off the last digit of a given number?

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Here's my solution. However, what are you supposed to do if there are no even digits in the number?

int findLastEvenDigit(int n)
{
   lastDigit = n % 10;
   if (lastDigit % 2 == 0) return lastDigit;
   else return findLastEvenDigit(n/10);
}

Assumptions: No negative numbers (not sure/relevant if it will work for them)