Decimal to Binary Conversion

I was writing a function for conversion between Decimal and Binary base number systems and here's my original code:

void binary(int number)
{
    vector<int> binary;

    while (number == true)
    {
        binary.insert(binary.begin(), (number % 2) ? 1 : 0);
        numbe开发者_StackOverflow中文版r /= 2;
    }

    for (int access = 0; access < binary.size(); access++)
        cout << binary[access];
}

It didn't work however until I did this:

while(number)

what's wrong with

while(number == true)

and what's the difference between the two forms? Thanks in advance.

---

When you say while (number), number, which is an int, is converted to type bool. If it is zero it becomes false and if it is nonzero it becomes true.

When you say while (number == true), the true is converted to an int (to become 1) and it is the same as if you had said while (number == 1).

---

Here is my code....

    #include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<math.h>
#include<unistd.h>
#include<assert.h>
#include<stdbool.h>
#define max 10000
#define RLC(num,pos) ((num << pos)|(num >> (32 - pos)))
#define RRC(num,pos) ((num >> pos)|(num << (32 - pos)))

void tobinstr(int value, int bitsCount, char* output)
{
    int i;
    output[bitsCount] = '\0';
    for (i = bitsCount - 1; i >= 0; --i, value >>= 1)
      {
             output[i] = (value & 1) + '0';
      }
}


  int main()
   {
    char s[50];
    tobinstr(65536,32, s);
    printf("%s\n", s);
    return 0;
   }