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Is this ReceiveFromAsync() bug?

开发者 https://www.devze.com 2023-03-01 04:22 出处:网络
this is my first question and I\'m not English native speaker so sorry for my (maybe) inaccurate English.

this is my first question and I'm not English native speaker so sorry for my (maybe) inaccurate English.

I'm implementing real-time network engine and using Socket.xxxAsync() method.

I made a UDP socket at server-side like this.

m_udpSock = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
m_udpSock.Bind(new IPEndPoint(IPAddress.Any, udpPort));
SocketAsyncEventArgs udpRecvArg = new SocketAsyncEventArgs();
udpRecvLoopStart(m_udpSock, udpRecvArg);

(udpPort is known to client.)

    private void udpRecvLoopStart(Socket udpSocket, SocketAsyncEventArgs udpRecvArg)
    {            
        udpRecvArg.AcceptSocket = udpSocket;
        byte[] udpRecvBuffer = new byte[NetworkEngineConst.MsgSizeMax];
        udpRecvArg.SetBuffer(udpRecvBuffer, 0, udpRecvBuffer.Length);
        udpRecvArg.RemoteEndPoint = new IPEndPoint(IPAddress.Any, 0);
        udpRecvArg.Completed += new EventHandler<SocketAsyncEventArgs>(udpRecvArg_Completed);

        udpRecv(udpRecvArg);
    }

    private void udpRecv(SocketAsyncEventArgs udpRecvArg)
    { 
        bool synchronous = false;
        try
        {                
            synchronous = !udpRecvArg.AcceptSocket.ReceiveFromAsync(udpRecvArg);
        }
        catch (Exception e)
        {
            OnIOError("recvUdp()\n" + e.ToString());
            return;
        }
        if (synchronous)
            udpRecvArg_Completed(this, udpRecvArg);
    }

Completed event handler is this:

    void udpRecvArg_Completed(object sender, SocketAsyncEventArgs udpRecvArg)
    {
        EndPoint udpEp = udpRecvArg.RemoteEndPoint;            
        string msg = Encoding.UTF8.GetString(udpRecvArg.Buffer, 14, udpRecvArg.BytesTransferred - 14);
        Debug.WriteLine(udpEp + " " + msg);
        udpRecv(udpRecvArg);            
    }

( first 14 bytes are message prefix,CRC and sequence number)

And two(or more) clients send UDP packet to server. ( sending rate is hundreds per second )

For example, client1(192.168.0.1:50113) sends "11111111111111111111111111111", client2(192.168.0.1:59368) sends "2".

But sometimes(not always) endpoint is wrong. log is like below:

192.168.0.1:50113 11111111111111111111111111111

192.168.0.1:50113 1111111111111111111开发者_开发百科1111111111

192.168.0.1:50113 11111111111111111111111111111

192.168.0.1:59368 2

192.168.0.1:59368 2

192.168.0.1:50113 11111111111111111111111111111

192.168.0.1:59368 11111111111111111111111111111 <- wrong part

192.168.0.1:59368 2

192.168.0.1:50113 11111111111111111111111111111

192.168.0.1:50113 11111111111111111111111111111

192.168.0.1:50113 11111111111111111111111111111

192.168.0.1:59368 2

192.168.0.1:50113 11111111111111111111111111111

192.168.0.1:59368 2

192.168.0.1:59368 2

I doubt packet error, but there was no error in packet(I confirmed with Wireshark)

Is this a bug ?

(Add)

I tried

        m_udpSock = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
        m_udpSock.SetSocketOption(SocketOptionLevel.IP, SocketOptionName.PacketInformation, true);
        m_udpSock.Bind(new IPEndPoint(IPAddress.Any, udpPort));

and replaced ReceiveFromAsync() with ReceiveMessageFromAsync().

but SocketAsyncEventArgs.ReceiveMessageFromPacketInfo.Address is null

(Add) ReceiveMessageFromAsync() problem is a bug.

It is fixed in the .NET framework 4.0

here

thank you.


Maybe try using Socket.ReceiveMessageFromAsync and then get the packet data using ReceiveMessageFromPacketInfo .

FYI this is an alternative way to do it (see the Edit in the answer)

HTH

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