W开发者_开发百科hat is the problem with my ajax and php code? It always show cannot connect to mysql. My wamp server is already switch on, but why can't it run? I try my other code with connect mysql, it worked.
Client Side:
<html>
<head>
<script type="text/javascript">
function showUser(str)
{
if (str=="")
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="1">oscar</option>
<option value="2">charles</option>
<option value="3">fathur</option>
</select>
</form>
<br />
<div id="txtHint"><b>Person info will be listed here.</b></div>
</body>
</html>
Server Side
<?php
$q=$_GET["q"];
$con = mysql_connect('localhost', 'user', 'user123');
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("showuser", $con);
$sql="SELECT * FROM user WHERE id = '".$q."'";
$result = mysql_query($sql);
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "<td>" . $row['Age'] . "</td>";
echo "<td>" . $row['Hometown'] . "</td>";
echo "<td>" . $row['Job'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
It looks like your error is server side, check your logic there. Or if you want post your server side logic and we'll take a peep at it :) What you have posted there looks fine, no immediate errors come to mind...
Why don't you use a framework like JQuery?
Why reinvent the wheel?
Have a look of how simple it is:
$.ajax({
url: "test.html",
context: document.body,
success: function(){
$(this).addClass("done");
}
});
http://api.jquery.com/jQuery.ajax/
![Interactive visualization of a graph in python [closed]](https://www.devze.com/res/2023/04-10/09/92d32fe8c0d22fb96bd6f6e8b7d1f457.gif)
加载中,请稍侯......
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