Is this boolean test pythonic for limiting a list's members to a set of legal values?

I have a list of legal words:

legal = ['osama','bin','laden']

A function accepts a 开发者_JS百科list that must contain words in the legal list & returns true if every member of the list is a legal word.

def is_legal( list ):
   return not any( [tok not in legal for tok in list ] )

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It's easier to read if you use all() instead of any():

legal = set(['osama','bin','laden'])

def is_legal(seq):
    return all(tok in legal for tok in seq)

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You don't want the square brackets (since they force creation of a list), and you don't want to shadow builtins, but yes.

def is_legal(seq):
    return not any(tok not in legal for tok in seq)

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all((token in LEGAL_TOKENS) for token in mySequence)

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I prefer:

legal = {'osama','bin','laden'} # or set(['osama','bin','laden']) if not 2.7+
is_legal = legal.issuperset