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Storing data from SQL in array

开发者 https://www.devze.com 2023-03-06 08:32 出处:网络
I am trying to store the data from 开发者_运维技巧my sql database into an array.Currently I have this:

I am trying to store the data from 开发者_运维技巧my sql database into an array. Currently I have this:

$query = mysql_query("SELECT * FROM  `InspEmail` WHERE  `Company` LIKE  '$company'");

while($row = mysql_fetch_array($query))
    {

        $inspector = $row['name'];

    }

The problem is that I have 8 rows of data. I need to store each 8 names from that database into an array. When I try this:

$inspector = array($row['name']);

It doesn't work.


If you want to store all of the names in an array, you need to define the array outside the scope of the while loop and append to it. Like this:

$nameArray = array();
while($row = mysql_fetch_array($query)) {
    // Append to the array
    $nameArray[] = $row['name'];   
}


What you want is:

$inspector[] = $row['name'];

This will store all 8 names in an array similar to:

array(
     [0] => name1
     [1] => name2
     [2] => name3

)


Lots of good answers. But if you do this often, you might want to write a little function:

mysql_field_array($sql, $fieldname)
{
    $res = mysql_query($sql);
    $a = array();
    while($row = mysql_fetch_array($res))
    {
        $a[] = $row[$fieldname];
    }
    mysql_free_result($res);
    return $a;
}


Replace this line...

$inspector = $row['name'];

...with this:

$inspector [] = $row['name'];

After that, the inspector array contains all the names.


$query = mysql_query("SELECT * FROM  `InspEmail` WHERE  `Company` LIKE  '$company'");
$data = array();
while($row = mysql_fetch_array($query))
{
    $inspector[] = $row;
}
for($i=0;$i<mysql_num_rows($row);$i++)
{
  $data = $inspector[$i];
}
return $data;

Check it...

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