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How to alias a field or column in MySQL?

开发者 https://www.devze.com 2023-03-07 17:09 出处:网络
I\'m trying to do something like this. But I get an unknown c开发者_StackOverflow社区olumn error:

I'm trying to do something like this. But I get an unknown c开发者_StackOverflow社区olumn error:

SELECT SUM(field1 + field2) AS col1, col1 + field3 AS col3 from core

Basically, I want to just use the alias so that I won't need to perform the operations performed earlier. Is this possible in mysql?


select @code:= SUM(field1 + field2), @code+1 from abc;

But, please be aware of the following (from the MySQL 5.6 docs):

As a general rule, other than in SET statements, you should never assign a value to a user variable and read the value within the same statement. For example, to increment a variable, this is okay:

SET @a = @a + 1;

For other statements, such as SELECT, you might get the results you expect, but this is not guaranteed. In the following statement, you might think that MySQL will evaluate @a first and then do an assignment second:

SELECT @a, @a:=@a+1, ...;

However, the order of evaluation for expressions involving user variables is undefined.

So, use at your own risk.


Consider using a subquery, like:

SELECT col1
,      col1 + field3 AS col3 
FROM   (
       SELECT  field1 + field2 as col1
       ,       field3
       from    core
       ) as SubQueryAlias


You can select the alias:

SELECT SUM(field1 + field2) AS col1, (select col1) + field3 AS col3 from core

This works.


select @code:= SUM(field1 + field2), (@code*1) from abc;

@code*1 covert into numeric expression and you can use anywhere like

select @code:= SUM(field1 + field2), (@code*1)+field3 from abc;


Short answer is no:

mysql> select 1 as a, a + 1 as b;
ERROR 1054 (42S22): Unknown column 'a' in 'field list'

postgresql# select 1 as a, a + 1 as b;
ERROR:  column "a" does not exist

That said, some SQL implementations allow to use the aliases in where/group by/having clauses, e.g.:

postgresql# select 1 as a group by a; -- 1 row


In case you are using it with aggregate function (group by) and if it doesn't work for you place the calculated column to the end with forward column referecing.

SELECT FNC2(AF), FNC1(A) AS AF,  B, C,  FROM Table GROUP BY ...

1st one doesn't work due to forward column referencing. Do this instead 

SELECT FNC1(A) AS AF, B, C, FNC2((SELECT AF)) FROM Table GROUP BY ...

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