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Size开发者_高级运维 of character ('a') in C/C++
Why does this program output 4 and not 1?
void main()
{
printf("%d",int(sizeof('z')));
}
'z' is a character and sizeof('z') must print 1?
'z' is a character literal and in C a character literal is of type int. So sizeof('z') equals sizeof(int) on your implementation.
Sizeof char.
Perhaps surprisingly, character constants in C are of type int, so
sizeof('a')issizeof(int)
加载中,请稍侯......
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