Execute non-anonymous function on definition

I have the following code:

$(document).ready(function() {

    var myFunc = function () {
        alert('test');
    };

    myfunc();  

    jQuery('#type-selector').change(myFunc);
});

The purpose of this code is that I need function myFunc to be executed on both document.ready event and onChange event. This code works perfectly, however I wonder is there a way to avoid the call myFunc(); and execut开发者_如何学Goe the function on its definition instead? In other words I need to keep the reference on function object and execute function "in one line".

---

You could trigger the change event:

jQuery('#type-selector').change(function() {
    alert('test');
}).change();

or

jQuery('#type-selector').change(myFunc).change();

---

You can write

jQuery('#type-selector').change(
    (function() {
        alert('test');
        return arguments.callee;
    })()
);

This function returns itself when called (return arguments.callee).
I call the function immediately, then pass its return value 9which is the same function) to change as the event handler.

This is confusing code; I don't recommend using it.