Dynamic memory allocation - default-initialization of primitive types in c++

If I allocate an array of some primitive type e.g.

double *v = new double[10];

I need to know, what the inital value of the array entries will be.

Is it specified in the standard or compiler dependend and where can I find it.

开发者_如何学GoThanks, Johannes

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No, the array contents are not initialized. You need to use double *v = new double[10](); to have the default value of 0 for each element (Notice ()).