Bitwise AND on 32-bit Integer

How do you perform a bitwise AND operation on two 32-bit integers in C#?

开发者_C百科

Related:

Most common C# bitwise operations.

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With the & operator

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Use the & operator.

Binary & operators are predefined for the integral types[.] For integral types, & computes the bitwise AND of its operands.

From MSDN.

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var x = 1 & 5;
//x will = 1

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const uint 
  BIT_ONE = 1,
  BIT_TWO = 2,
  BIT_THREE = 4;

uint bits = BIT_ONE + BIT_TWO;

if((bits & BIT_TWO) == BIT_TWO){ /* do thing */ }

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use & operator (not &&)

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int a = 42;
int b = 21;
int result = a & b;

For a bit more info here's the first Google result:
http://weblogs.asp.net/alessandro/archive/2007/10/02/bitwise-operators-in-c-or-xor-and-amp-amp-not.aspx

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The & operator

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var result = (UInt32)1 & (UInt32)0x0000000F;

// result == (UInt32)1;
// result.GetType() : System.UInt32

If you try to cast the result to int, you probably get an overflow error starting from 0x80000000, Unchecked allows to avoid overflow errors that not so uncommon when working with the bit masks.

result = 0xFFFFFFFF;
Int32 result2;
unchecked
{
 result2 = (Int32)result;
}

// result2 == -1;