Can someone explain this C++ syntax?

I'm going through someone else's code and came across the following syntax:

typedef struct abc {

   abc() : member(0){}

   unsigned int member

}

It seems like a class with member variable and a constructor, except it is declared struct. I have two questi开发者_如何学Goons here.

1. Is this syntax supported in C?
2. What would be a reason to use structs over classes?

Thanks a lot in advance.

PS: how do I format the code?

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This is not valid C.

In C++, struct and class are essentially synonyms. The only difference is that members and inheritance are public by default in a struct, and private by default in a class.

There are no hard guidelines on whether to choose struct or class. However, you'll often find people using struct only for simple C-like plain old data structures ("PODs").

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This is most assuredly just C++. struct and class are identical in C++, except for defaulting to public instead of private for inheritance and class contents.

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In C++, struct and class are essentially the same thing, except that for a struct members are public by default. So just read it as you would a class.

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abc() is a constructor of class abc, member is a internal variable, constructor abc defaults set member as 0.

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1. The syntax is supported. The constructor initializes member to 0 and does nothing else.
2. struct has a default access of public.

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This is C++ code, however using typedef struct (that comes from C) in C++ code is awful. There is difference between C and C++ and in C++ you don't need to typedef structs. struct MyStruct is sufficient declaration if you want to refer your struct via MyStruct myStruct;. Mixing C with C++ is bad.