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jQuery Validation plugin with JQGrid?

开发者 https://www.devze.com 2022-12-14 23:39 出处:网络
Has 开发者_Go百科anyone successfully used the jQuery Validation plugin with JQGrid? I realize that JQGrid has its own validation scheme, but it\'s limited and a little clumsy; and I\'d prefer to reuse

Has 开发者_Go百科anyone successfully used the jQuery Validation plugin with JQGrid? I realize that JQGrid has its own validation scheme, but it's limited and a little clumsy; and I'd prefer to reuse the validation UI, language, and rules that I'm using with the rest of my forms.


Edit inline and Validations is possibile with this steps.

Write your function to highlight and unhilight your input box:

GridErrorHighlight = function(el, er, ev) {
    $(el)
        .addClass('ui-state-error')
    .parent()
        .addClass('ui-state-error');
}

GridErrorUnHighlight = function(el, er, ev) {
    $(el)
        .removeClass('ui-state-error')
    .parent()
       .removeClass('ui-state-error');
}

Extend jqgrid:

; (function($) {
    $.jgrid.extend({
        onErrorHighlight: GridErrorHighlight,
        onUnHighlight: GridErrorUnHighlight,
    });
})(jQuery);

Now is easy for jQuery validation plugin use your custom functions. Is only necessary to create this options and initialize validation plugin:

var table = $('#tableid').jqGrid({});

var validateOpt = {
        meta: "validate",
        highlight: table.onErrorHighlight,
        unhighlight: table.onUnHighlight
    };

$(document).ready(function() {
    $('#formId').validate(val);
});

Now is easy to set validator for single input cell. We use jqGrid EditOptions into Model to add custom class for validation:

"editoptions":{"class":" {validate: { range:[0,1] } }"}

that's all!

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