Translate this if statement in to regex

I had to translate the following if statement in to a regex so we could use it on a whole string

if (buffer[i] < 32 && !(buffer[i] == '\t' || buffer[i] == '\r' || buffer[i] == '\n'))
    buffer[i] = ' ';

Which I did by doing this

return Regex.Replace(base.ReadLine(), "[\0-\x08\x0B\x0C\x0E-\x1F]", " ");

However I don't like the way it looks, is there a way in regex to do the same thing I did in 开发者_运维技巧the if statement? Basicly

[\0-\x1f]~[\t\r\b]

Where the ~ would go the thing that represents "exclude the following" (It does not have to be this exact syntax, I was just wondering if there is something like this?)

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Take a look here - it talks about regex negations. I'm not sure if it can directly help you, but it's the best I've got.

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If you don't like the look of your regex, you could use something like /(?![\t\r\n])[\x00-\x1F]/. The first part, (?![\t\r\n]), says to fail if the next character matches [\t\r\n], and then the second part [\x00-\x1F] says to match any character <= 0x1F.

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To negate something, use [^\t\r\b]. You can also try negative lookbehinds but the former is simpler IMHO.