batch script to set a variable with the current path location

How can I set a variable with the current location? For instance, if I get in c:\test and want to set the variable to test and if I get inside c:\test\test2 the variable will be set to开发者_JAVA百科 test2.

I'm thinking about using a for to get inside a lot of folders and check if some file exists, if the correct file exist I want to set the current folder to a variable so I can copy the path and copy the folder.

The main problem deals with copying the rest of the files is the same folder as the .inf file.

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The current directory is in the "shadow" variable cd.
You could try

set "var=%cd%"

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%~dp0

This expands into the drive & path of the currently running batch file. I usually surround my batch files with something like:

@echo off
pushd %~dp0

...

popd

Edit: It seems I didn't understand the OP. My example gets the location of the currently running script, not the "Current Directory". +1 to jeb.

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I think there is a little confussion here. %CD% always have the current directory, so you don't need to add anything to have it. However, by rereading your original question, I think that you need the LAST PART of the current directory, that is, the name of the current location excluding all previous locations. If so, then you may use this:

set i=0
:nextdir
set /a i+=1
for /f "tokens=%i% delims=\" %%a in ("%CD%") do if not "%%a" == "" set lastdir=%%a& goto nextdir
echo Current location: %lastdir%