Passing variables to an included file

I have a template class which goes like this:

class Template{
public $pageTitle = "";
public function __construct($pageTitle){
    $this->pageTitle = $pageTitle;
}

public function display(){
    include "/includes/head.php";
    include "/includes/body.php";
}
}

Now, I'm used to Java's workings but I don't understand why I'm 开发者_如何学运维getting an undefined variable ($pageTitle) error. The included files need to be able to access that variable. I know it's going to be very simple but I actually haven't found out why. What do I need to do to allow includes to see this variable?

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The includes will also have to use $this->pageTitle. Effectively, the include makes them part of the method body.

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The included file lives in the same scope as your object. So you need to call:

$this->pageTitle

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If you don't want to do the whole $this->, you can do something like the following... The extract function will extract the array $this->data into variables with names respective to the key/index of each item. So now you will be able to do echo $pageTitle;

class Template{
   public $data = Array();

   public function __construct($pageTitle){
        $this->data['pageTitle'] = $pageTitle;
   }

   public function display(){
        extract($this->data);
        include "/includes/head.php";
        include "/includes/body.php";
   }
}

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Scope is a little different in PHP than in java. For your specific case you need

$this->pageTitle

To access a variable declared outside the class, you'll need to make it global

global $myVar;