Get protocol, domain, and port from URL

I 开发者_StackOverflow中文版need to extract the full protocol, domain, and port from a given URL. For example:

https://localhost:8181/ContactUs-1.0/contact?lang=it&report_type=consumer
>>>
https://localhost:8181

---

const full = location.protocol + '//' + location.host;

---

None of these answers seem to completely address the question, which calls for an arbitrary url, not specifically the url of the current page.

Method 1: Use the URL API (caveat: no IE11 support)

You can use the URL API (not supported by IE11, but available everywhere else).

This also makes it easy to access search params. Another bonus: it can be used in a Web Worker since it doesn't depend on the DOM.

const url = new URL('http://example.com:12345/blog/foo/bar?startIndex=1&pageSize=10');

Method 2 (old way): Use the browser's built-in parser in the DOM

Use this if you need this to work on older browsers as well.

//  Create an anchor element (note: no need to append this element to the document)
const url = document.createElement('a');
//  Set href to any path
url.setAttribute('href', 'http://example.com:12345/blog/foo/bar?startIndex=1&pageSize=10');

That's it!

The browser's built-in parser has already done its job. Now you can just grab the parts you need (note that this works for both methods above):

//  Get any piece of the url you're interested in
url.hostname;  //  'example.com'
url.port;      //  12345
url.search;    //  '?startIndex=1&pageSize=10'
url.pathname;  //  '/blog/foo/bar'
url.protocol;  //  'http:'

Bonus: Search params

Chances are you'll probably want to break apart the search url params as well, since '?startIndex=1&pageSize=10' isn't too useable on its own.

If you used Method 1 (URL API) above, you simply use the searchParams getters:

url.searchParams.get('startIndex');  // '1'

Or to get all parameters:

function searchParamsToObj(searchParams) {
  const paramsMap = Array
    .from(url.searchParams)
    .reduce((params, [key, val]) => params.set(key, val), new Map());
  return Object.fromEntries(paramsMap);
}
searchParamsToObj(url.searchParams);
// -> { startIndex: '1', pageSize: '10' }

If you used Method 2 (the old way), you can use something like this:

// Simple object output (note: does NOT preserve duplicate keys).
var params = url.search.substr(1); // remove '?' prefix
params
    .split('&')
    .reduce((accum, keyval) => {
        const [key, val] = keyval.split('=');
        accum[key] = val;
        return accum;
    }, {});
// -> { startIndex: '1', pageSize: '10' }

---

For some reason all the answers are all overkills. This is all it takes:

window.location.origin

More details can be found here: https://developer.mozilla.org/en-US/docs/Web/API/window.location#Properties

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first get the current address

var url = window.location.href

Then just parse that string

var arr = url.split("/");

your url is:

var result = arr[0] + "//" + arr[2]

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As has already been mentioned there is the as yet not fully supported window.location.origin but instead of either using it or creating a new variable to use, I prefer to check for it and if it isn't set to set it.

For example;

if (!window.location.origin) {
  window.location.origin = window.location.protocol + "//" + window.location.hostname + (window.location.port ? ':' + window.location.port: '');
}

I actually wrote about this a few months back A fix for window.location.origin

---

host

var url = window.location.host;

returns localhost:2679

hostname

var url = window.location.hostname;

returns localhost

---

Why not use:

let full = window.location.origin

---

window.location.origin will be enough to get the same.

---

The protocol property sets or returns the protocol of the current URL, including the colon (:).

This means that if you want to get only the HTTP/HTTPS part you can do something like this:

var protocol = window.location.protocol.replace(/:/g,'')

For the domain you can use:

var domain = window.location.hostname;

For the port you can use:

var port = window.location.port;

Keep in mind that the port will be an empty string if it is not visible in the URL. For example:

• http://example.com/ will return "" for port
• http://example.com:80/ will return 80 for port

If you need to show 80/443 when you have no port use

var port = window.location.port || (protocol === 'https' ? '443' : '80');

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Indeed, window.location.origin works fine in browsers following standards, but guess what. IE isn't following standards.

So because of that, this is what worked for me in IE, FireFox and Chrome:

var full = location.protocol+'//'+location.hostname+(location.port ? ':'+location.port: '');

but for possible future enhancements which could cause conflicts, I specified the "window" reference before the "location" object.

var full = window.location.protocol+'//'+window.location.hostname+(window.location.port ? ':'+window.location.port: '');

---

Here is the solution I'm using:

const result = `${ window.location.protocol }//${ window.location.host }`;

EDIT:

To add cross-browser compatibility, use the following:

const result = `${ window.location.protocol }//${ window.location.hostname + (window.location.port ? ':' + window.location.port: '') }`;

---

var http = location.protocol;
var slashes = http.concat("//");
var host = slashes.concat(window.location.hostname);

---

var getBasePath = function(url) {
    var r = ('' + url).match(/^(https?:)?\/\/[^/]+/i);
    return r ? r[0] : '';
};

---

Try use a regular expression (Regex), which will be quite useful when you want to validate / extract stuff or even do some simple parsing in javascript.

The regex is :

/([a-zA-Z]+):\/\/([\-\w\.]+)(?:\:(\d{0,5}))?/

Demonstration:

function breakURL(url){

     matches = /([a-zA-Z]+):\/\/([\-\w\.]+)(?:\:(\d{0,5}))?/.exec(url);

     foo = new Array();

     if(matches){
          for( i = 1; i < matches.length ; i++){ foo.push(matches[i]); }
     }

     return foo
}

url = "https://www.google.co.uk:55699/search?q=http%3A%2F%2F&oq=http%3A%2F%2F&aqs=chrome..69i57j69i60l3j69i65l2.2342j0j4&sourceid=chrome&ie=UTF-8"


breakURL(url);       // [https, www.google.co.uk, 55699] 
breakURL();          // []
breakURL("asf");     // []
breakURL("asd://");  // []
breakURL("asd://a"); // [asd, a, undefined]

Now you can do validation as well.

---

With ES6 template literals:

const url = `${location.protocol}//${location.hostname}${location.port?':'+location.port:''}`;

document.getElementById("result").innerText = url;

<div id="result"></div>

And you can simplify to:

const url = `${location.protocol}//${location.host}`;

document.getElementById("result").innerText = url;

<div id="result"></div>

---

Simple answer that works for all browsers:

let origin;

if (!window.location.origin) {
  origin = window.location.protocol + "//" + window.location.hostname + 
     (window.location.port ? ':' + window.location.port: '');
}

origin = window.location.origin;

---

ES6 style with configurable parameters.

/**
 * Get the current URL from `window` context object.
 * Will return the fully qualified URL if neccessary:
 *   getCurrentBaseURL(true, false) // `http://localhost/` - `https://localhost:3000/`
 *   getCurrentBaseURL(true, true) // `http://www.example.com` - `https://www.example.com:8080`
 *   getCurrentBaseURL(false, true) // `www.example.com` - `localhost:3000`
 *
 * @param {boolean} [includeProtocol=true]
 * @param {boolean} [removeTrailingSlash=false]
 * @returns {string} The current base URL.
 */
export const getCurrentBaseURL = (includeProtocol = true, removeTrailingSlash = false) => {
  if (!window || !window.location || !window.location.hostname || !window.location.protocol) {
    console.error(
      `The getCurrentBaseURL function must be called from a context in which window object exists. Yet, window is ${window}`,
      [window, window.location, window.location.hostname, window.location.protocol],
    )
    throw new TypeError('Whole or part of window is not defined.')
  }

  const URL = `${includeProtocol ? `${window.location.protocol}//` : ''}${window.location.hostname}${
    window.location.port ? `:${window.location.port}` : ''
  }${removeTrailingSlash ? '' : '/'}`

  // console.log(`The URL is ${URL}`)

  return URL
}

---

window.location.protocol + '//' + window.location.host

---

console.log(`${req.protocol}://${req.get('host')}/${req.originalUrl}`);

• req.protocol - gives the protocol you used (e.g. HTTP)
• req.get(host) - gives the host name with the port number (e.g. localhost:8080)