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MySQL: Grouping results

开发者 https://www.devze.com 2023-03-29 23:47 出处:网络
How can I group my results in a query such as this: SELECT ( SELECT SUM(wky) FROM table WHERE Earnings_Date BETWEEN \'2011-08-14\' AND \'2011-08-16\'

How can I group my results in a query such as this:

SELECT (
             SELECT SUM(wky) FROM table
             WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16'
            ) +
            (SELECT SUM(earnings) FROM table
            WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16') / .75

The above query returns wky+(earnings/.75) for all the sites (each site has a wky and earnings number for different dates. Where would I put a group by in the above query? I would like my r开发者_如何学Goesults to be grouped by site_id, since the above query just returns the sum of the earnings of all of them.

Thanks!


SELECT site_id, (SUM(wky) + (SUM(earnings) / 0.75)) 
FROM Earnings_Date
WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16'
GROUP BY site_id

Your data comes from the same table for both queries, so you can combine them.


SELECT (
         SELECT SUM(wky) FROM table
         WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16'
        ) +
        (SELECT SUM(earnings) FROM table
        WHERE Earnings_Date BETWEEN '2011-08-14' AND '2011-08-16') / .75

, site_id GROUP BY site_id

:)

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