How does one draw a tilted ellipse in ImageDraw?

I am trying to draw a tilted ellipse in image draw. However, I am not sure how to define it, since while the scheme below would move the points, I think this would just squish the ellipse, not rotate it (also I think there is something slightly wrong with the transformation in any case). I am feeding the output of this function into the ellipse command and adding it to an existing picture, so any methods that would rotate the entire image are no good. OD is just a square offset to the coordinate center I am using.

def ellipsebound(major, minor, tilt=0, offset=0,  angle=0):
    #creates a bound for an ellispe, defined with tilt meaning to rotate the orthogonal axis and angle corresponds to rotating the ellipse position
    angle = radians(angle)
    tilt = radians(tilt)
    box=(
    1 + int(ceil((OD+offset*cos(angle)+(major*cos(tilt)+minor*sin(tilt)))/conv)), 
    1 + int(ceil((OD+offset*sin(angle)+(major*sin(tilt)-minor*cos(tilt)))/conv)),
 int(ceil((2*OD-(OD-offset*cos(angle)-(major*cos(tilt)+minor*sin(tilt)))/conv))),
 int(ceil((2*OD-(OD-offset*sin(angle)-(major*sin(tilt)-minor*cos(tilt)))/conv)))
 开发者_StackOverflow中文版) #create bounding box
    return box

Does anyone know how to accomplish this?

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It looks like the 'box' that is being used to draw the ellipse has no rotation associated with it. It is simply defined by the (left, top, right, bottom) extents.

One possible workaround (depending on what you need to do) is to draw the ellipse (sized correctly, but without the rotation) onto an intermediary image, use the image.rotate() method, and then paste it into your target image.

I hope that helps.