Php Error on Displaying Third row

<option value='$row2['cID']'>".$row2['prefix']."

Throws an error:

开发者_Go百科

syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in

This code works fine:

<option>".$row2['prefix']." "."</option><br />

How can I add the cID in?

Thanks

---

Fix your quoting

"<option value='" . $row2['cID'] . "'>".$row2['prefix']."

Or better: enclose the whole thing in double-quotes and enclose the array elements in {}

"<option value='{$row2['cID']}'>{$row2['prefix']}</option>"

---

Try :

$foo = "<option value='".$row2['cID']."'>".$row2['prefix']."";

---

You can't use the single quotes for the "value"

use:

"<option value='" . $row2['cID'] . "'>" . $row2['prefix'] . "</option>"

---

$cID = $row2['cID'];
$prefix = $row2['prefix'];

echo <<< EOF
<option value="$cID">$prefix</option><br />
EOF;