jQuery: How can I select multiple elements from one path?

I'm curious if there is a way to condense this:

$('foo input:checkbox, foo input:radio');

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I tried the following but no luck:

• $('foo input[type="checkbox",type="radio"]');
  

  This blindly doesn't work (prob bad syntax)

•  $('foo input[type="checkbox"][type=开发者_JAVA技巧"radio"]');
  

  I think this would select all inputs that are both radio and checkbox, which won't ever be the case.

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Edit:

I changed fooElement to foo toi simplify the example

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$('input[type="checkbox"], input[type="radio"]', $('fooelement'))

Or

$('[type="checkbox"], [type="radio"]', $('fooelement input'))

Or

$(':checkbox, :radio', $('fooelement input'))

Remember jQuery offers the abiltiy to specify a context to search in.

http://api.jquery.com/jQuery/

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Try this

$('fooElement input').filter(":checkbox, :radio");

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$('fooElement').find(':checkbox,:radio');

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$('fooElement input[type="checkbox"]').add('fooElement [type="radio"]');

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it's not really "condensed", per se, but:

$('fooElement input[type="checkbox"], fooElement input[type="radio"]');