$("#id_btnquizzestwo").click(function() {
    $temp = $("#rightsideeightone").is(":visible");     
    if($temp) {
        $("#rightsideeightone").css('display') = 'none';    
    }
})
The rightsideeightone division is not being hidden.
What to do ?
$("#id_btnquizzestwo").click(function() {
    $temp = $("#rightsideeightone").is(":visible");
    //alert($temp);
    if($temp) {
        $("#rightsideeightone").hide();         
    }
    $temp2 = $("#rightsideeighttwo").is(":hidden");
    //alert($temp2);
    if($temp2) {
        $("#rightsideeighttwo").show();
    }
})
I tried this, the rightsideeighttwo is not being visible. Initialy the rightsideeightone is visible and the rightsideeighttwo is hidden.
<div id="rightsideeight" >
    <div id="id_pollsquizzes" >
        <?php echo '<ul>'; ?>
        <?php
            echo '<li>';
            echo $this->Form->button('Polls',array('type'=>'button','id'=>'id_btnpollstwo'));
            echo '</l开发者_如何学编程i>';
            echo '  ';
            echo '<li>';
            echo $this->Form->button('Quizzes',array('type'=>'button','id'=>'id_btnquizzestwo'));
            echo '</li>';
            echo '  ';
        ?>
    </div>
    <div id="rightsideeightone" style="visibility: visible" >
            ......................
    </div>
    <div id="rightsideeighttwo" style="visibility: hidden" >
            ......................
    </div>
</div>
The line
$("#rightsideeightone").css('display') = 'none';
is incorrect. To change a style property, use this syntax:
$("#rightsideeightone").css('display','none'); 
Checking the visibility isn't necessary - if the element $("#rightsideeightone") is already hidden then hiding it again has no effect, so your function can be written as:
$("#id_btnquizzestwo").click(function() {
        $("#rightsideeightone").css('display','none');
});
Assuming that the $temp variable equals false you could try:
$('#rightsideeightone').hide();
All three explanation should work. But just for clarification:
Using this:
$("#rightsideeightone").css('display') = 'none';
Isn't working due to .css('display') this is a getter. As in get the current value of the display property. So what you are basically doing here is first getting the value (say 'block') and then try to assign a new value ('none') to it. It would be the equivalent of: (just for explanation, doesn't actually work):
'block' = 'none';
You need to set the value of display on the element not just overwrite the propert you get. Hence use the jQuery setter:
$("#rightsideeightone").css('display','none'); 
// OR
$("#rightsideeightone").css({ display: 'none' });
I prefer the later one.
Hope I explained it more the confused it :)
http://jsfiddle.net/LQg7W/89/
.visible { display: block; }
.hidden { display: none; }
$("#id_btnquizzestwo").click(function() {
  if( $("#rightsideeightone").is(".visible") )
    $("#rightsideeightone").removeClass("visible").addClass('hidden');
  if( $("#rightsideeighttwo").is(".hidden") )
    $("#rightsideeighttwo").removeClass("hidden").addClass('visible');
});
 
         
                                         
                                         
                                         
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