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How to pass the value of an option field as well as an input box via post in jquery/PHP?

开发者 https://www.devze.com 2023-04-03 15:13 出处:网络
I have a search bar like <div id=\"searchbar\"> <form> <select name=\"Cars\"> <option value=\"big\">Big Cars</option>

I have a search bar like

<div id="searchbar">
<form>
<select name="Cars">
<option value="big">Big Cars</option>
<option value="small">Small Cars</option>
</select>
<input type ='text' name="searchkey" id ="search" onblur ='setTimeout('removeSearchSuggestions()', 20);' onkeyup ='getSearchSuggestions(this.value);'/>
&nbsp;
<br/>
<div id = 'searchsuggest'></div>
<input type ='submit' value = 'Search' />
</form>
</div>

and i have the following jquery code snippet

function getSearchSuggestions(value){
   if (value !=""){
   $.post("searchSuggest.php", {searchPart:value}, function(data) {
     $("#searchsuggest").html(data);
     doSearchCSS();
   });
   } else {
    removeSearchSuggestions开发者_运维问答();
    }

  }

So searchSuggest has access to "searchPart" i.e. the value that is typed into the input box. I am modifying something I got to work for a case without options. How do I modify the jquery function to access the selected option in searchSuggest.php?

Thanks!


This will help you: http://api.jquery.com/selected-selector/

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