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How to sum two objects?

开发者 https://www.devze.com 2023-04-04 11:57 出处:网络
I want to do an application that pareses text. So far, I have a class called Result, that holds the value and type each part of an equation.

I want to do an application that pareses text. So far, I have a class called Result, that holds the value and type each part of an equation.

public enum ResultType
{
    Int32,
    Double,
    Boolean,
    Color,
    DateTime,
    String,
    Undefined,
    Void
}

public class Result
{
    public object Value { get; set; }
    public ResultType Type { get; set; }
}

Possible Result's could be:

 5 : Int32
 true : Boolean 
 DADACC : Color 
 "Hello World!" : String 
 10.0 : Double 
 13/11/1986 : DateTime

Now I want to开发者_开发百科 sum/divide/pow/... two Results but I really don´t want to do all the work. In C#, you can mix them all together and get an answer.

var value = "Hello" + 2.0 + 4 + DateTime.Today; (value = "Hello2413/09/2011 12:00:00 a.m.")

Is there an easy way to handle this? Or do I have to figure out all combos by myself? I´m thinking about something like:

var Operator = "+"; // or "-","*","/","^","%"
var sum = DoTheCSharpOperation(Operator, ResultA.Value, ResultB.Value)
var sumResult = new Result(sum);


This sounds to me like a perfect application for the "dynamic" keyword:

using System;
using System.Diagnostics;

namespace ConsoleApplication33 {
  public static class Program {
    private static void Main() {
      var result1=DoTheCSharpOperation(Operator.Plus, 1.2, 2.4);
      var result2=DoTheCSharpOperation(Operator.Plus, "Hello", 2.4);
      var result3=DoTheCSharpOperation(Operator.Minus, 5, 2); 

      Debug.WriteLine(result1); //a double with value 3.6
      Debug.WriteLine(result2); //a string with value "Hello2.4"
      Debug.WriteLine(result3); //an int with value 3
    }

    public enum Operator {
      Plus,
      Minus
    }

    public static object DoTheCSharpOperation(Operator op, dynamic a, dynamic b) {
      switch(op) {
        case Operator.Plus:
          return a+b;
        case Operator.Minus:
          return a-b;
        default:
          throw new Exception("unknown operator "+op);
      }
    }
  }
}
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