TSQL - Select the rows with the higher count and when count is the same, the row with the higher id value

HELP!!! I'm stumped and have tried several options to no avail... I need to return one row for each Pub_id, and the row that is returned should be the one with the higher Count and when there is more than one row with the highest count, I need the one with the higher price_id.

I have populated a table with this data...

pub_id, price_id,   count
7,  59431,            5
22, 39964,            4
39, 112831,           3
39, 120715,           2
47, 95359,            2
74, 142825,           5
74, 106688,           5
74, 37514,            1

---

and This is what I need to return...

pub_id, price_i开发者_如何学Cd,   count
7,  59431,            5
22, 39964,            4
39, 112831,           3
47, 95359,            2
74, 142825,           5

---

;WITH T
     AS (SELECT *,
                ROW_NUMBER() OVER (PARTITION BY pub_id 
                               ORDER BY [count] DESC, price_id DESC) AS rn
         FROM   your_table)
SELECT pub_id,
       [count],
       price_id
FROM   T  
WHERE rn=1

---

Do you want something like this

select pub_id,
       Count,
       Price_Id
from   (select Pub_id,
               max(count),
               Price_Id
        from   table_name
        group  by Pub_id) der_tab
group  by Pub_id,
          Count
having Price_id = max(price_Id)