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Why do I get "Too many open files" errors?

开发者 https://www.devze.com 2023-04-07 18:27 出处:网络
I find myself having to explicitly call System.gc() in my Groovy scripts to prevent errors like the one below. Why doesn\'t the garbage collector do this for me? Is there something I can do to cause i

I find myself having to explicitly call System.gc() in my Groovy scripts to prevent errors like the one below. Why doesn't the garbage collector do this for me? Is there something I can do to cause it to garbage collect to prevent these errors (maybe JAVA_OPTS)?

Caught: java.util.concurrent.ExecutionException: org.codehaus.groovy.runtime.InvokerInvocationException: java.io.IOException: Cannot run program "ls": java.io.IOException: error=24, Too many open files
    at groovyx.gpars.GParsPool.runForkJoin(GParsPool.groovy:305)
    at UsageAnalyzer$_run_closure2_closure6.doCall(UsageAnalyzer.groovy:36)
    at groovyx.gpars.GParsPool$_withExistingPool_closure1.doCall(GParsPool.groovy:170)
    at groovyx.gpars.GParsPool$_withExistingPool_closure1.doCall(GParsPool.groovy)
    at groovyx.gpars.GParsPool.withExistingPool(GParsPool.groovy:169)
    at groovyx.gpars.GParsPool.wit开发者_如何学JAVAhPool(GParsPool.groovy:141)
    at groovyx.gpars.GParsPool.withPool(GParsPool.groovy:117)
    at groovyx.gpars.GParsPool.withPool(GParsPool.groovy:96)
    at UsageAnalyzer$_run_closure2.doCall(<removed>)
    at UsageAnalyzer.run(<removed>)

This stack trace is from a parallel program but it happens in sequential programs as well.


As you're using groovy, you can use the convenient methods such as File.withReader(), File.withWriter(), File.withInputStream(), InputStream.withStream() to ensure resources get closed cleanly. This is less cumbersome than using Java's try .. finally idiom, as there's not need to explicitly call close(), or declare a variable outside the try block.

e.g. to read from a file.

File f = new File('/mumble/mumble/')
f.withReader{ r -> 
   // do stuff with reader here
}


Definitely look for any place you open files or streams and make sure you close them. It's often beneficial to wrap them like this:

final InputStream in = ...;
try
{
    // Do whatever.
}
finally
{
    // Will always close the stream, regardless of exceptions, return statements, etc.
    in.close();
}
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