Is this possible to count index posistion of my current node that belonging to the child of <w:body> using xslt2.0?

This is my Xml Document.

<w:document xmlns:w="w">
<w:body>
   <w:p>
        <w:r>
           <w:t>
               Para1
            </w:t>
        </w:r>
     </w:p>
   <w:p>
        <w:r>
           <w:t>
               Para2
            </w:t>
        </w:r>
     </w:p>
   <w:p>
        <w:r>
           <w:t>
               Para3
            </w:t>
        </w:r>
     </w:p>
   <w:p>
        <w:r>
           <w:t>
               Para4
            </w:t>
        </w:r>
     </w:p>
   <w:p>
        <w:r>
           <w:t>
               Para5
            </w:t>
        </w:r>
     </w:p>

   <w:tbl>
         <w:tr>
            <w:tc>
               <w:p>
                  <w:r>
                    <w:t>
                         Para6
                    </w:t>
                   </w:r>
                </w:p>
              </w:tc>
            <w:tc>
               <w:p>
                  <w:r>
                    <w:t>
                         Para7 <!-- Just Assume, this is current Node -->
                    </w:t>
                   </w:r>
                </w:p>
              </w:tc>
           </w:tr>
        </w:tbl>
     <w:p>开发者_JAVA技巧
        <w:r>
           <w:t>
               Para8
            </w:t>
        </w:r>
     </w:p>

</w:body>
</w:document>

So, now i want to get the index position of current node that belonging to the child of <w:body>.So My expected output is :6.

for example,

1. if current node is para6 then my output is also 6.
2. if current node is para8 then my output is 7.
3. if current node is para5 then my output is 5.

If possible, Please Guide me to get this...

New Update:

<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                              xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main"
                              xmlns:v="urn:schemas-microsoft-com:vml"
                              xmlns:pic="http://schemas.openxmlformats.org/drawingml/2006/picture"
                              xmlns:exsl="http://exslt.org/common"
                              xmlns:fn="http://www.w3.org/2005/xpath-functions"
                              extension-element-prefixes="exsl">


  <xsl:output method="html" indent="yes"/>

    <xsl:template match="*">
      <Document>
         <xsl:apply-templates select="//w:p">
         </xsl:apply-templates>
      </Document>
    </xsl:template>

  <xsl:template match="w:p">

       <xsl:variable name="index">
            <xsl:call-template name="get-para-index">
                 <xsl:with-param name="node" select="."/>
            </xsl:call-template>
       </xsl:variable>

     <Paragraph>
            <xsl:attribute name="index">
                 <xsl:value-of select="$index" />
            </xsl:attribute>

            <xsl:apply-templates select="./w:r/w:t"/>
     </Paragraph>

  </xsl:template>

  <xsl:template match="w:t">
    <xsl:value-of select="."/>
  </xsl:template>

  <xsl:template name="get-para-index">
       <xsl:param name="node"/>
    <xsl:value-of select="count($node/ancestor::*[parent::w:body]/preceding-sibling::*)+1"/>     <!-- Need to write logic here -->
  </xsl:template>

</xsl:stylesheet>

I just calling the get-para-index template for get the index position of each and every <w:p>.But it returns always 1 for every <w:p>. Please Guide me to get out of this problem...

Thanks & Regards, P.SARAVANAN

---

I'm not 100% sure of what you want but this expression

count(ancestor::*[parent::w:body]/preceding-sibling::*)+1

from the context node, finds the ancestor whose parent is <w:body>, then selects all preceding sibling elements and counts those. Adding 1 should give you the position.

---

My Updated Xslt that fulfilled my requests...

<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                              xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main"
                              xmlns:v="urn:schemas-microsoft-com:vml"
                              xmlns:pic="http://schemas.openxmlformats.org/drawingml/2006/picture"
                              xmlns:exsl="http://exslt.org/common"
                              xmlns:fn="http://www.w3.org/2005/xpath-functions"
                              extension-element-prefixes="exsl">


  <xsl:output method="html" indent="yes"/>

    <xsl:template match="*">
      <Document>
         <xsl:apply-templates select="//w:p">
         </xsl:apply-templates>
      </Document>
    </xsl:template>

  <xsl:template match="w:p">

       <xsl:variable name="index">
            <xsl:call-template name="get-para-index">
                 <xsl:with-param name="node" select="."/>
            </xsl:call-template>
       </xsl:variable>

     <Paragraph>
            <xsl:attribute name="index">
                 <xsl:value-of select="$index" />
            </xsl:attribute>

            <xsl:apply-templates select="./w:r/w:t"/>
     </Paragraph>

  </xsl:template>

  <xsl:template match="w:t">
    <xsl:value-of select="."/>
  </xsl:template>

  <xsl:template name="get-para-index">
       <xsl:param name="node"/>

    <xsl:choose>
      <xsl:when test="$node/ancestor::*[parent::w:body]">
        <xsl:value-of select="count($node/ancestor::*[parent::w:body]/preceding-sibling::*)"/>
      </xsl:when>
      <xsl:otherwise>
        <xsl:value-of select="count($node/preceding-sibling::*)"/>
      </xsl:otherwise>
    </xsl:choose>          
  </xsl:template>

</xsl:stylesheet>