jQuery Cycle Plugin For Loop

I have been stumped trying to figure out how to integrate a simple for loop to work with the jQuery Cycle plugin. In my basic example I am trying to create 15 cycle functions using jquery .hover() and .cycle().

for(i=1;i<15;i++){
    $(".t"+ i).hover(function() {
        $('.projectTitle').cycle(i);
    });
}

If I create 15 separate functions(per below) the script runs fine but I am in need of simplifying my code.

$('.t1').hover(function() {
开发者_JAVA百科    $('.projectTitle').cycle(1);
});
$('.t2').hover(function() {
    $('.projectTitle').cycle(2);
});
$('.t3').hover(function() {
    $('.projectTitle').cycle(3);
});
$('.t4').hover(function() {
    $('.projectTitle').cycle(4);
});
...

Any help would be greatly appreciated.

---

You can circumvent the whole closure issue by storing i as a data attribute in the DOM element itself:

for (var i=1; i<=15; i++) {
    $('.t'+i).data("inc",i).hover(function() { 
        $('.projectTitle').cycle( $(this).data("inc") ); 
    });
}

(Incidentally, you should probably replace all those classes with IDs, for performance.)

The "right" way to do this is with a JavaScript closure, which I'm no expert in, but I think should look like this:

for (var i=1; i<=15; i++) {
    $('.t'+i).hover(
        (function() { 
            var a = i;
            return function() { $('.projectTitle').cycle( a ); }
        })()
    );
}

---

If they are in the correct order in the DOM you can use the index provided by jQuery's each and give them all the same class:

$('.t').each(function(index) { 
    $(this).mouseover( function() { // Use mouseover instead of hover, otherwise your function will be run on mouseover AND mouseout
        $('.projectTitle').cycle( index ); 
    }
});