Is it possible to force particular registers in inline assembly code?

I have the following assembly code:

  __asm__ __volatile__ (
  "1: subi %0, 1"        "\n\t"
  "brne 1b"
  : "=d" (__count)
  : "M" (__count));

which results in the following compiler ouptut

  ce:   81 50           subi    r24, 0x01   ; 1
  d0:   f1 f7           brne    .-4         ; 0xce <main>
  d2:   80 e0           ldi r24, 0x00   ; 0
  d4:   90 e0           ldi r25, 0x00   ; 0

How can i achieve the following:

  ce:   81 50           subi    r16, 0x01   ; 1
  d0:   f1 f7           brne    .-4         ; 0xce <main>
  d2:   80 e0           ldi r16, 0x00   ; 0

Is it even possible to tell th开发者_JAVA技巧e compiler to use r16 instead of r24:r25? That way i can reduce the cycle count by 1 which is used by the ldi r25,0x00 line.

Thanks Jack

---

This question is old and you most certainly already solved it, but for archiving purposes, let me answer it: yes, you can. Declare __count like this:

register <type> __count __asm__ ("r16");

And voilá! Using the GNU extension explicit register variables, you've declared that the C variable __count should always be placed in r16 wherever it is used - including outside of an ASM call.

Note that this declaration should have local scope, otherwise the compiler will avoid using this register in other functions.

---

Check out this: http://www.nongnu.org/avr-libc/user-manual/inline_asm.html#io_ops

It seems you can't force it to use a specific register. However, if you use "=a" instead of "=d" you would restrict it to registers r16..r23 which should be what you want (because you just don't want it to use the 'paired' registers r24/r25)