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Copy a matrix to a subset of another matrix

开发者 https://www.devze.com 2023-04-11 10:59 出处:网络
I\'m having difficulty copying a subset of a matrix into another larger matrix using OpenCV in C++. I tried the following code:

I'm having difficulty copying a subset of a matrix into another larger matrix using OpenCV in C++.

I tried the following code:

#include <opencv2/opencv.hpp>

void printMatrix(const cv::Mat &M, std::string matrix)
{
    printf("Matrix \"%s\" is %i x %i\n", matrix.c_str(), M.rows, M.cols);
    std::cout << M << std::endl;
}

int main(int argc, char ** argv)
{
    cv::Mat P0(3, 4, CV_32F);
    printMatrix(P0, "P0 Initial");

    cv::Mat R0 = cv::Mat::eye(3,3,CV_32F);
    printMatrix(R0, "R0 I");

    R0.copyTo(P0.colRange(0,2));
    printMatrix(P0, "P0 with R");

    return 0;
}

Which produces the following output:

Matrix "P0 Initial" is 3 x 4
[-4.3160208e+008, -4.3160208e+开发者_StackOverflow008, -4.3160208e+008, -4.3160208e+008;
-4.3160208e+008, -4.3160208e+008, -4.3160208e+008, -4.3160208e+008;
-4.3160208e+008, -4.3160208e+008, -4.3160208e+008, -4.3160208e+008]

Matrix "R0 I" is 3 x 3
[1, 0, 0;
0, 1, 0;
0, 0, 1]

Matrix "P0 with R" is 3 x 4
[-4.3160208e+008, -4.3160208e+008, -4.3160208e+008, -4.3160208e+008;
-4.3160208e+008, -4.3160208e+008, -4.3160208e+008, -4.3160208e+008;
-4.3160208e+008, -4.3160208e+008, -4.3160208e+008, -4.3160208e+008]

While suggests that the copy operation is not doing anything.

I found a similar post here but updating the relevant line to the following as suggested in that post still produces the same output.

//R0.copyTo(P0.colRange(0,2));
cv::Mat dest = P0.colRange(0,2);
printMatrix(P0, "P0 with R");


Your code doesn't compile for me. I get an error at R0.copyTo(P0.colRange(0,2)); (and also if I try R0.copyTo(P0.colRange(0,3)); which has the correct range.) But this does work for me:

    cv::Mat dest(P0.colRange(0,3));
    R0.copyTo(dest);
    printMatrix(P0, "P0 with R");

You almost had it in your last code example, but you left out copyTo (and your range was incorrect).

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