开发者

How to request administrator permissions when the program starts?

开发者 https://www.devze.com 2023-04-11 14:13 出处:网络
I need my software to be able to run as administrator on Windows Vista (if someone runs it without administrative permissions, it will crash).

I need my software to be able to run as administrator on Windows Vista (if someone runs it without administrative permissions, it will crash).

When launching other software, I've seen a prompt by the system like "this software will run as administrator. do you want to continue?" when the app was trying to acquire administr开发者_如何转开发ative privileges.

How do I request administrative privileges when running an c# app on Windows Vista?


Add the following to your manifest file:

<requestedExecutionLevel level="requireAdministrator" uiAccess="false" />

You can also use highestAvailable for the level.

Look here about embedding manifest files:

http://msdn.microsoft.com/en-us/library/bb756929.aspx

PS: If you don't have a manifest file, you can easily add a new one:

In Visual Studio, right click project -> Add Item -> Choose Application Manifest File ( under General for Visual C# items)

The added file will already have the above part, just change the level to requireAdministrator from asInvoker


Put this XML in a file called yourexename.exe.manifest:

<assembly xmlns="urn:schemas-microsoft-com:asm.v1" manifestVersion="1.0">
<trustInfo xmlns="urn:schemas-microsoft-com:asm.v3">
   <security>
     <requestedPrivileges>
        <requestedExecutionLevel level="highestAvailable" />
     </requestedPrivileges>
   </security>
</trustInfo>
</assembly>


You need to use the requestedExecutionLevel token in a manifest:

http://www.developerfusion.com/code/7987/making-a-net-app-run-on-vista-with-administrator-priviledges/


For .Net (Visual Studio 2013), include a manifest file that request administrator elevation and using the compiler's /win32manifest flag, compose and provide a manifest file that requests this elevation. However, the following describe doing so within Visual Studio for a project name, App.Exe:

  1. Create a file with the following content (for convenience you may add the file to the Visual Studio project as a development resource by ensuring that it's Build Action is None and Copy to Output... is Do not copy. By convention manifest files are named after their output target, in this case App.Exe.manifest. If you require uiAccess (User Interface), the assembly must be strongly named.

    <?xml version="1.0" encoding="utf-8" ?>
    <asmv1:assembly manifestVersion="1.0" 
        xmlns="urn:schemas-microsoft-com:asm.v1"
        xmlns:asmv1="urn:schemas-microsoft-com:asm.v1"
        xmlns:asmv2="urn:schemas-microsoft-com:asm.v2"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
      <assemblyIdentity version="1.0.0.0" name="App" />
      <trustInfo xmlns="urn:schemas-microsoft-com:asm.v2">
        <security>
          <requestedPrivileges xmlns="urn:schemas-microsoft-com:asm.v3">
            <requestedExecutionLevel level="requireAdministrator" uiAccess="false" />
          </requestedPrivileges>
        </security>
      </trustInfo>
    </asmv1:assembly>
    
  2. Edit the project dialogue's build panel Other flags: entry field to add the win32manifest flag and have Visual Studio invoke the compiler accordingly. For example, in this case,

    /win32manifest:App.Exe.manifest.

Note the following entry:

  <trustInfo xmlns="urn:schemas-microsoft-com:asm.v2">
    <security>
      <requestedPrivileges xmlns="urn:schemas-microsoft-com:asm.v3">
        <requestedExecutionLevel level="requireAdministrator" uiAccess="false" />
      </requestedPrivileges>
    </security>
  </trustInfo>
0

精彩评论

暂无评论...
验证码 换一张
取 消

关注公众号