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Can I execute the command for each result of the file globbing in zsh without for?

开发者 https://www.devze.com 2023-04-12 21:51 出处:网络
I am searching for away to execute the current command for each res开发者_运维问答ult of the file globbingwithout building a for loop. I saw this somewhere but can\'t remember where exactly.

I am searching for away to execute the current command for each res开发者_运维问答ult of the file globbing without building a for loop. I saw this somewhere but can't remember where exactly.

(The echo is just an example, it should also work with psql for example)

Example:

$ touch aaa bbb ccc ddd
$ echo "--- " [a-c]*
---  aaa bbb ccc

Desired output:

---  aaa
---  bbb
---  ccc

Kown way:

$ for i in [a-c]*; do echo "--- " $i ; done
---  aaa
---  bbb
---  ccc

Could be done using for. But maybe there is a way to do it shorter? Maybe like using double curly braces around the glob or whatever?

Thanks. :)


You may be looking for zargs, a command with the same purpose as xargs but a saner interface.

autoload -U zargs
zargs -n 1 -- * -- mycommand


The printf command will implicitly loop if given more arguments than placeholders in the format string:

printf -- "--- %s\n"  [a-c]*

To execute a command on each file, you need xargs: I assume you have GNU xargs that has the -0 option:

printf "%s\0" [a-c]* | xargs -0 -I FILE echo aa FILE bb

Replace the echo xargs command with whatever you need, using the "FILE" placeholder where you need the filename.

Use your own judgement to determine if this is actually better or more maintainable than a for-loop.

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