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Drupal 6 - how to set up a VIEWS block?

开发者 https://www.devze.com 2023-04-12 22:53 出处:网络
I can\'t figure out how to set up a block view for this in Drupal 6: Users submit a picture.If it is approved, I upload it to the site.

I can't figure out how to set up a block view for this in Drupal 6:

Users submit a picture. If it is approved, I upload it to the site.

There is a node that shows the details of the picture and the author information. I wan开发者_StackOverflow中文版t to have a block that says, MORE BY THIS AUTHOR. This block would list more images that this author has submitted. How can I do this?

The URL is: mysite/content/name-of-image so I don't know how to create a view that shows all the images by this author since the user name is not in the URL. Can someone tell me how to do this?

Thank you.


  • Add a user:uid argument to the view.
  • choose "provide deafult argument" option for this argument.
  • choose "php code" as default argument type.
  • enter following php code:

    if (arg(0) == 'node' && is_numeric(arg(1))) {  
        $node = node_load(arg(1));  
        $uid = $node->uid;  
    }  
    return $uid;
    

in your case you want the uid from a cck field of the node, so the php code should be this:

if (arg(0) == 'node' && is_numeric(arg(1))) {  
    $node = node_load(arg(1));
    //if the field contains a user id
    $uid = $node->field_authorid[0][value];

    //if the field contains a username
    $user = user_load(array('name' => check_plain($node->field_authorname[0][value]))); 
    $uid = $user->uid; 
}  
return $uid;

Now you'll have the author user id from the node in url. Now you can add fields to the view from nodes created by this author.

NOTE: the view preview won't show any results, so you'll have to save this view and test it outside the views builder.

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