Linker : how to place a block of data at a specific address boundary

This may be an easy question but I am a beginner with the linker file of GNU GCC (codesourcery arm-none-eabi ver 4.5.2).

I have to initialize the Mmu in a ARM7 processor and in datasheet, it is said that the Mmu page table must be located at a 16kbyte (2^14) boundary.

For now I have come with this solution, but I'm almost certain that this is not the more efficient one!

ENTRY(_start)

SECTIONS
{
 . = 0x0;
 .text : {_stext = .;
*startall.o (.text)
. = 0x4000;
*MmuSdram0.o (.text)
*(.text)
_etext = .;}
 .data : {_sdata = .;
*(.data) 
_edata = .;}
 .bss : {_sbss = .;
*(.bss) 
_ebss = .;}
}

startall.o is an assembly file containing processor initialisation.

Next line, I set the address to 0x4000 (boundary of 2^14).

MmuSdram0.o is containing the Mmu page table.

Then f开发者_StackOverflowollow the rest of the firmware.

Obviously, this solution give me a gap between the end of startall and 0x4000, which i a waste of memory space(I don't like waste ;-)

What I would do instead is to put the pagetable after the *(.text) but I don't know how to do something like :

*(.text) "except" MmuSdram0.o

And I prefer to let the linker place the page table at the next available 2^14 boundary instead of fixing the address myself. I checked in the linker documentation, found ALIGN command, but I'm not sure how to use it correctly or if this even the command that fit my need...

Thanks in advance!

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hmm, place the __attribute__ (( aligned(16*1024) )) before the semicolon ';' of your mmu table declaration