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Adding values in a tuple that is in a list in python

开发者 https://www.devze.com 2022-12-19 04:57 出处:网络
I retrieve some data from a database which returns it i开发者_C百科n a list of tuple values such as this: [(1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,

I retrieve some data from a database which returns it i开发者_C百科n a list of tuple values such as this: [(1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,)]

Is there a function that can sum up the values in the list of tuples? For example, the above sample should return 18.


>>>> l=[(1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,)]

>>> sum(map(sum,l))
18

>>> l[0]=(1,2,3,)
>>> l
[(1, 2, 3), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,)]
>>> sum(map(sum,l))
23


>>> l = [(1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,)]
>>> s = sum(i[0] for i in l)
>>> print s
18


Just some fun with itertools, not very readable. Works only if you consider 1st element in tuple.

>>> import itertools
>>> l = [(1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,), (1,)]
>>> sum(*itertools.izip(*l))
18
0

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